Question

69. The average age of 06 persons living
in a house is 23.5 years. Three of them are
majors and their average age is 42 years.
The difference in ages of the three minor
children is same. What is the mean of the
ages of minor children?
a. 3 years
b. 4 years
c. 5 years
d. 6 years​

Answer 1

Answer:

5 years

Step-by-step explanation:

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Answer 2

The mean of the ages of minor children is 5 years

Given :

• The average age of 6 persons living in a house is 23.5 years.

• Three of them are majors and their average age is 42 years.

• The difference in ages of the three minor children is same.

To find :

The mean of the ages of minor children is

a. 3 years

b. 4 years

c. 5 years

d. 6 years

Solution :

Step 1 of 3 :

Calculate sum of the ages of 6 persons

Here it is given that the average age of 6 persons living in a house is 23.5 years.

∴ Sum of the ages of 6 persons

= 6 × 23.5 years

= 141 years

Step 2 of 3 :

Calculate the sum of ages of the three majors

Three of them are majors and their average age is 42 years.

∴ Sum of ages of the three majors

= 3 × 42 years

= 126 years

Step 3 of 3 :

Calculate the mean of the ages of minor children

Here it is given that the difference in ages of the three minor children is same.

∴ Sum of the ages of three minor children

= 141 years - 126 years

= 15 years

So the mean of the ages of minor children

$\displaystyle \sf = \frac{15 }{3} \: \: years$

$\displaystyle \sf = 5 \: \: years$

Hence the correct option is c. 5 years

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