69)Two wires of same material have length L and 2L and cross?sectional areas 4/
and A respectively. The ratio of their specific resistance would be
ho
O 1:2
O 8:1
O 1:8
O 1:1
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Given: Two wires of same material have length L and 2L and cross sectional areas 4/ and A respectively.
We have to find: The ratio of their specific resistance would be
Explanation:
The correct option is O 1:8
- The specific resistance () of a conductor is a property of the material.
- Its value is only affected by the conductor's material and temperature. Its value is independent of the conductor's length and cross-sectional area.
As R = ρ₁/A
R ∝ 1/A
R₁/R₂ = 1₁/A₁ × A₂/1₂
R₁/R₂ = L/4A × A/2L = 1:8
1₁ = L
1₂ = 2L
A₁ = 4A
A₂ = A
Hence, from the given options, the correct option is 1:8.
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