6a^2-a-15 factorise by splitting mid term
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Answered by
74
6a²-a - 15 = 0
∴ 6a² - 10a + 9a -15 = 0
∴ 2a ( 3a - 5 ) + 3 ( 3a - 5 ) = 0
∴ ( 2a + 3 ) ( 3a - 5 ) = 0
∴ 2a + 3 = 0 or 3a - 5 = 0
∴ a = -3/2 or a = 5/3.
Hope this helps you !!
# Dhruvsh
∴ 6a² - 10a + 9a -15 = 0
∴ 2a ( 3a - 5 ) + 3 ( 3a - 5 ) = 0
∴ ( 2a + 3 ) ( 3a - 5 ) = 0
∴ 2a + 3 = 0 or 3a - 5 = 0
∴ a = -3/2 or a = 5/3.
Hope this helps you !!
# Dhruvsh
Answered by
44
6a² - a -15
= 6a² + 9a - 10a - 15
= 3a (2a + 3) - 5 (2a + 3)
= (3a - 5)(2a + 3)
a = 5/3 OR a = -3/2
= 6a² + 9a - 10a - 15
= 3a (2a + 3) - 5 (2a + 3)
= (3a - 5)(2a + 3)
a = 5/3 OR a = -3/2
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