Question

(6a+5b+4c-5a)(6a-5b+4c-5a)​

Answer 1

Step-by-step explanation:

It is Given that,

$(6a + 5b + 4c - 5a)(6a - 5b + 4c - 5a)$

Now add ,

$= > (a + 5b + 4c)(a - 5b + 4c)$

Now,

${a}^{2} - 5ab + 4ac - 25 {b}^{2} + 5ab + 20bc + 4ac - 20bc + 16 {c}^{2}$

Cutt Common no.s,

${a}^{2} - 25 {b}^{2} + 16 {c}^{2} + 8ac$

Now ,

We Know That,

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

Reaarange the No.

$= > {a}^{2} + 16 {c}^{2} + 8ac - 25 {b}^{2}$

So it will become,

${(a + 4c)}^{2} - 25 {b}^{2}$

Hence Solveddd!!!

Hope it Helpsss!!!