Question

LEVEL 2
25. An electron is accelerated through a potential difference of 10 V. Find thede Brogliewavelength associat
the electron. Assume that the mass of an electron is 91 X 10-31 kg.​

Answer 1

Explanation:

lambda=h/√2meV

V = 10 volts

Potential energy gained by electron= eV,

where e is charge of electron .

Potential Energy = Kinetic Energy

eV = 0.5 mv²

1.6×10^(-19) × 10 = 0.5×9.1×10^(-31)v²

v² = (3.2/9.1)× 10^(18)

= 0.35164835 × 10^18

v = 0.59299945 × 10^9

= 6 × 10^8

λ = h/mv

= 6.626176 x 10^(-34) /[9.1*10^(-31)× 6 × 10^8]

= [ 6.626176/(54.6) ]× 10^(-34+23)

= 0.12135853 × 10^(-11)

= 1.2 × 10^(-11) m approx.