Question

6a2-7a-9 and 9a2+10a+5​

Answer 1

$\huge\orange{\textbf{\textsf{Answer:}}}$

$\small{ }$

$\large\bf\color{navy}{To~solve:}$

$\sf{~~~~~~~~~~~(6a^{2}-7a-9)+(9a^{2}+10a+5)}$

$\sf{: \implies 6a^{2}-7a-9+9a^{2}+10a+5}$

$\sf{: \implies (6a^{2}+9a^{2})+(-7a+10a)+(-9+5)}$

$\sf{: \implies {\underline{\boxed{\tt 15a^{2}+3a-4}}}}$

$\small{ }$

$\huge\orange{\textbf{\textsf{Hope~it~helps..!!}}}$

Answer 2

Step-by-step explanation:

6a

2

−7a−9)+(9a

2

+10a+5)

\sf{: \implies 6a^{2}-7a-9+9a^{2}+10a+5}:⟹6a

2

−7a−9+9a

2

+10a+5

\sf{: \implies (6a^{2}+9a^{2})+(-7a+10a)+(-9+5)}:⟹(6a

2

+9a

2

)+(−7a+10a)+(−9+5)

\sf{: \implies {\underline{\boxed{\tt 15a^{2}+3a-4}}}}:⟹

15a

2

+3a−4