6a³+3a²-3a
factorise it
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Answer:
Write
a
3
−3a
2
+3a+7=a
3
−3a
2
+3a−1+8=(a−1)
3
+8
But
(a−1)
3
+8=(a−1)
3
+2
3
=(a−1+2)[(a−1)
2
−2(a−1)+4]
Simplification gives
[(a−1)
2
−2(a−1)+4]=a
2
−2a+2−2a+1+4=a
2
−4a+7
Thus we obtain
a
3
−3a
2
+3a+7=(a+1)(a
2
−4a+7).
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