Question

6costheeta + 8sintheeta =9 prove only brainliers can do it ​

Answer 1

Answer:

MATHS

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Asked on December 27, 2019 by

Ashafal Kondvilkar

If α and β are two different values θ lying between 0 and 2π which satisfy the equation 6cosθ+8sinθ=9. Find sin(α+β).

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ANSWER

6cosθ+8sinθ=9

6cosθ=9−8sinθ

squaring.

36cos

2

θ=81+64sin

2

θ−144sinθ

36(1−sin

2

θ)=81−144sinθ+64sin

2

θ

100sin

2

θ−144sinθ+45=0

α&βarediffValuesofθ

thenproductofroots=sinαsinβ=

100

45

20

9

Again8sinθ=9−6cosθ

64sin

2

θ=81+36cos

2

θ−108cosθ

100cos

2

θ−108cosθ+17=0

productofroots=cosαcosβ=

100

17

Nowcosαcosβ−sinαsinβ=

100

17

−

100

45

cos(α+β)=

25

−7

sin(α+β)=

25

24

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Answer 2

Answer:

thanks but three hor brainlist chaiye