Chemistry, asked by nandanachandrapbpf8l, 9 months ago

6g H2 reacts with 8 g oxygen to give water. After the completion of reaction, what is the limiting reagent?(with explanation)
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Answers

Answered by anishkabalyan29
2

Answer:

2H2+O2→2H2O

10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol  10 g = 5 mol 

 64 of oxygen  (molar mass 32 g/mol) = 32 g/mol  64 g = 2 mol 

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.

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