6g H2 reacts with 8 g oxygen to give water. After the completion of reaction, what is the limiting reagent?(with explanation)
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Answer:
2H2+O2→2H2O
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol
64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g = 2 mol
As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.
2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.
Here, oxygen is the limiting reagent and hydrogen is the excess reagent.
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