6h(3x+5y) + (3x + 5y)
3k(z-3) -h(z-3)
plz answer these with full working..i will mark as brainliest if right answer
it is urgent
Iris16:
i really dont know what to do
both answers are right!!!
I think you have to factorise
its just that i never grt algebra
even though this is not for me
its for my sis
um, thats ok . You will get it
Feel free to ask your doubts. I will try my best to answer them.
thnk u
:-)
Answers
Answered by
1
Solution 1.)
6h ( 3x +5y) + (3x+5y)
=> (3x+5y) (6h + 1)
Solution 2.)
3k ( z-3) - h(z-3)
=> (z-3) (3k - h)
6h ( 3x +5y) + (3x+5y)
=> (3x+5y) (6h + 1)
Solution 2.)
3k ( z-3) - h(z-3)
=> (z-3) (3k - h)
Answered by
0
If we have to factorise the following ,
here's your answer
1)
6h(3x+5y) + (3x + 5y)
it can also be written as 6h(3x+5y) + 1(3x + 5y)
Taking (3x + 5y) as common factor
we have,
(6h + 1)(3x + 5y) is the answer
2)
3k(z-3) -h(z-3)
Taking (z - 3) as common factor ,
we have
(3k - h)(z - 3)
here's your answer
1)
6h(3x+5y) + (3x + 5y)
it can also be written as 6h(3x+5y) + 1(3x + 5y)
Taking (3x + 5y) as common factor
we have,
(6h + 1)(3x + 5y) is the answer
2)
3k(z-3) -h(z-3)
Taking (z - 3) as common factor ,
we have
(3k - h)(z - 3)
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