Question

6k/7-(8k/9-k/3) with explaining​

Answer 1

According to BODMAS, we solve the brackets first

6k/7 - (8k/9 - k/3)

6k/7 - (8k/9 - 3k/9)

6k/7 - (5k/9)

Now, we have to get both denominators the same, which we do by taking the LCM of 7 & 9 = 63

6k/7 * 9/9 = 54/63

5k/9 * 7/7 = 35/63

Now, we can subtract:

(54-35)/63

=19/63

Hope this Helped!

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