Math, asked by shubham123495, 10 months ago

6k + 8 = 2k^2 , solve for k, with full process​

Answers

Answered by nitikasaini58
1

Answer:

6k+ 8 = 2k ²

2k²–6k–8=0

2(k²–3k ‐4)=0

2(k²–4k + k –4 )=0

2{k(k–4)+1(k–4)}=0

2{(k+1)(k–4)}=0

2k+2+2k–8=0

4k–6=0

4k=6

k=6÷4

k=3/2

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