Question

6m²– 3m- 2 =0 using formula​

Answer 1

• As per the given data, we have to solve the given equation.

          Given data:- $6m^{2} -3m-2=0$

          To find:- $6m^{2} -3m-2=0$

          Solution:-

• Observing the above equation we know that we can solve this equation by using QUADRATIC FORMULA.
• Quadratic formula is

                       $D=\frac{-b\frac{+}{-}\sqrt{b^{2}-4ac } }{2a}$    

   so we get,

                      $a=6$

                      $b=-3$  

                      $c=-2$  

Now put the value a,b,and c in the above quadratic formula

So that ,

                $D=\frac{-(-3)\frac{+}{-}\sqrt{(-3)^{2}-4(6(-2)) } }{2(6)}\\D=\frac{3\frac{+}{-}\sqrt{57} }{12}$

• Simplifying the above expression we get two equations i.e $D=\frac{3+\sqrt{57} }{12}$and$D=\frac{3-\sqrt{57} }{12}$.

Answer 2

Given : 6m²– 3m- 2 =0

To find 6m²– 3m- 2 =0

As per the given condition we need to solve the equation by the  quadratic formula.

Quadratic formula is

       D =  $\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

we get

    $a = 6\\b=-3\\c=-2$

  now put the value in the above equation a,b and c in the formula

let,

  $D=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(6(-2))}}{2(6)}$

$D=\frac{3 \pm \sqrt{57}}{12}$

Simplifying the above expression we get two equations

$D=\frac{3-\sqrt{57}}{12}$

$D=\frac{3+\sqrt{57}}{12}$