Question

..6points!!!!

Only give step by step explaination.....

A cuboidal tin open at the top has dimensions 20 cm x 16 cm x 14 cm. What is the total area of a sheet of metal required to make 10 such boxes?

Answer(13,280)cm^2


Explain....

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Answer 1

$\huge\bf\underline{\underline{Given:}}$

Length of cuboid = 20cm

Breadth of cuboid = 16cm

Height of cuboid = 14cm

$\huge\bf\underline{\underline{To\:Find:}}$

Total area of sheet required to make 10 such boxes

$\huge\bf\underline{\underline{Solution:}}$

Area of sheet required for 1 box

= Total surface area of cuboid

= 2(lb + bh + hl)

= 2[(20)(16) + (16)(14) + (14)(20)]

= 2(320 + 224 + 280)

= 2(824)

= 1648$\sf{cm^2}$

Area of sheet required for 10 box

= Area of sheet required for 1 box × 10

= 1648 × 10

= 16480$\sf{cm^2}$

Therefore,area of sheet of metal required to make 10 such boxes is 16480 sq.cm.

________________________

@ItsMysteriousGirl

Answer 2

SOLUTION:-

Given:

A cuboidal tin open at the top has dimensions 20cm×16cm×14cm.

To find:

The total area of a sheet of metal required to make 10 such boxes.

Explanation:

We know that, formula of the surface area of open box tin:

2(length+breadth)× height + length ×breadth

We have,

• Length of tin box,L= 20cm.
• Breadth of tin box,B=16cm.
• Height of tin box,H= 14cm.

According to the question:

Putting the value of given in above these formula.

Surface area of open tin= 2(20cm+16cm)× 14cm+20cm× 16cm

Surface area of open tin= 28(36)cm² +320cm²

Surface area of open tin= 1008cm² +320cm²

Surface area of open tin= 1328cm².

Now,

The total area of a sheet of metal required to make 10 such boxes;

⇒(10 × 1328)cm²

⇒ 13280cm²