Question

6power-1+8power-1as a whole in bracket + 3power -1 +2power -1in bracket power-1

Answer 1

$Value \: of \:(6^{-1} + 8^{-1}) + (3^{-1} + 2^{-1})^{-1} \\= \frac{1}{6} + \frac{1}{8} + \Big( \frac{1}{3} + \frac{1}{2}\Big)^{-1}$

$\boxed {\pink { Since, a^{-n} = \frac{1}{n} }}$

$= \frac{4+3}{24} + \Big( \frac{2+3}{6}\Big)^{-1} \\= \frac{7}{24} + \Big(\frac{5}{6}\Big)^{-1} \\= \frac{7}{24} + \frac{6}{5}\\= \frac{35+144}{120}\\= \frac{179}{120}$

Therefore.,

$\red {Value \: of \:(6^{-1} + 8^{-1}) + (3^{-1} + 2^{-1})^{-1}} \\\green { = \frac{179}{120}}$

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