If i cap jcap and k cap are unit vector along three mutually perpendicular directions then i cap . J cap = 1 and..
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The complete question is,
If i cap jcap and k cap are unit vector along three mutually perpendicular directions then i cap . J cap = 1 and. (i−j).{(j−k)×(k−i)}=
Given
( i − j ) . { ( j − k ) × ( k − i ) }
= ( i − j ) . ( j × k − j × i − k × k + k × i )
= ( i − j ) ( i + k − 0 + j )
= i . i + i . k + i . j − j . i − j . k − j . j
= i² + 0 + 0 − 0 − 0 − j²
= i² − j²
= 1 − 1
= 0
∴ ( i − j ) . { ( j − k ) × ( k − i ) } = 0
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