Question

6x+10y=42, 8x+12y=48 find the value of x and y?​

Answer 1

Answer:

Step-by-step explanation:

Given that,

6x + 10y = 42 and 8x + 12y = 48

2 ( 3x + 5y ) = 2 ( 21 ) and 4 ( 2x + 3y ) = 4 ( 12 )

Let 3x + 5y = 21 -----eq ( 1 ) and 2x + 3y = 12 -------eq ( 2 )

Now multiplying eq ( 1 ) with 2 and eq ( 2 ) with 3 ,we get

2 ( 3x + 5y = 21 ) and 3 ( 2x + 3y = 12 )

6x + 10y = 42 ------eq ( 3 ) and 6x + 9y = 36 ------eq ( 4 ) ( say)

On subtracting eq ( 3 ) - eq ( 4 ) ,we have

6x + 10y - 6x - 9y = 42 - 36

y = 6.

On substituting " y = 6 " in eq ( 3 ) , we have

6x + 10 ( 6 ) = 42

6x + 60 = 42

6x = 42 - 60

6x = - 18

x = - 18 / 6 = - 3.

Therefore, x = - 3 and y = 6 is the answer.