(6x^2-11x+7) (3x-4)
Answers
Answered by
20
Answer:
18x^3-57x^2+65x-28
Step-by-step explanation:
Given that,
(6x^2-11x+7)(3x-4)
=>(6x^2)(3x)-(11x)(3x)+7(3x)-4(6x^2)+4(11x)-4(7)
=>18x^3-33x^2+21x-24x^2+44x-28
=>18x^3-57x^2+65x-28
therefore,
(6x^2-11x+7)(3x-4)=18x^3-57x^2+65x-28
Hope this would be helpful for you
Answered by
0
Answer:
Step-by-step explanation:
Answer:
18x^3-57x^2+65x-28
Step-by-step explanation:
Given that,
(6x^2-11x+7)(3x-4)
=>(6x^2)(3x)-(11x)(3x)+7(3x)-4(6x^2)+4(11x)-4(7)
=>18x^3-33x^2+21x-24x^2+44x-28
=>18x^3-57x^2+65x-28
therefore,
(6x^2-11x+7)(3x-4)=18x^3-57x^2+65x-28
Hope this would be helpful for you
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