Question

6x^2-12. Solve this quadratic eqn nd find the zeros

Answer 1

Answer:

$\sqrt{2} \: \: and \: \: - \sqrt{2}$

Step-by-step explanation:

${6x}^{2} - 12 = 0 \\ 6( {x}^{2} - 2) = 0 \\ {x}^{2} - 2 = 0 \\ x = \sqrt{2} \: \: and \: \: - \sqrt{2}$

#hope it help uh..

BRAINLIEST PLSS

Answer 2

Step-by-step explanation:

$6x {}^{2} - 12 \\ \\ 6(x {}^{2} - 2) \\ \\ 6(x - \sqrt{2} )(x + \sqrt{2} )$

so , zeros are

$\sqrt{2} \: \: and \: \: - \sqrt{2}$

Hope it helps