6x^2+17x+12 what is the answer
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6x^2+17x+12
= 6x^2+8x+9x+12
=2x(3x+4)+3(3x+4)
=(2x+3)(3x+4)
= 6x^2+8x+9x+12
=2x(3x+4)+3(3x+4)
=(2x+3)(3x+4)
Answered by
9
sol=
In 6x2+17x+12, split the middle term so that the product of the two coefficients is equal to product of the coefficients of first and third term.
As product of coefficients of first and third term is 6×12=72, 17x can be split into 8x and 9x. Hence
6x2+17x+12=6x2+8x+9x+12
= 2x(3x+4)+3(3x+4)
= (2x+3)(3x+4)
In 6x2+17x+12, split the middle term so that the product of the two coefficients is equal to product of the coefficients of first and third term.
As product of coefficients of first and third term is 6×12=72, 17x can be split into 8x and 9x. Hence
6x2+17x+12=6x2+8x+9x+12
= 2x(3x+4)+3(3x+4)
= (2x+3)(3x+4)
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