6x^2 - 3x - 7x, Find the value of α^2+β^2 .
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Answers
Answered by
1
Answer:
6x
2
−3−7x
=6x
2
−7x−3
=6x
2
−9x+2x−3
=3x(2x−3)+1(2x−3)
=(2x−3)(3x+1)
x=
2
3
, x=
3
−1
The zeros of the polynomial....
of α^2+β^2 . 3x
... hope this will help you...
Answered by
1
Answer:
-50/24
Step-by-step explanation:
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