Question

6x^2 y^3 z^4 by cube 3 into z^3​

Answer 1

Answer:

We know that,

a

3

+b

3

+c

3

=(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)+3abc

If a+b+c=0, then a

3

+b

3

+c

3

=3abc

Now, given (x−2y)

3

+(2y−3z)

3

+(3z−x)

3

Here, a=(x−2y), b=(2y−3z), c=(3z−x) and a+b+c=(x−2y)+(2y−3z)+(3z−x)=0

Therefore

(x−2y)

3

+(2y−3z)

3

+(3z−x)

3

=3(x−2y)(2y−3z)(3z−x)

Step-by-step explanation:

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Answer 2

Answer:

3 ( x-2 y ) (2 y -3 z )

Step-by-step explanation:

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