Question

6x+3y=7xy , 3x+9y=11xy by substitution method

Answer 1

6x+3y=7xy
3x+9y=11xy

6x/xy +3y/xy=7
3x/xy +9y/xy=11

6/y + 3/x=7
3/y + 9/x=11

let 1/y=a and 1/x=b

6a +3b=7.........1
3a + 9b=11........2

a=7-3b upon 6....3
putting equation 3 in 2

3(7-3b upon 6 )+ 9b=11
21- 9b/6+9b=11
21-9b+54b/6=11
21+45b=66
45b=66-21=45
b=1
so
a=7-3(1)/6
a=4/6
a=2/3

Answer 2

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