Math, asked by ansariafsha786, 8 months ago

6x-4y=-12;8x-3y=-2. D. DX. DY answer​

Answers

Answered by kmahima922
0

Answer:

Final Answer: x= 2 , y = 6

Solution : Cramer,s Rule :Most awesome Method to solve linear Equations

Steps:

1)

We have,

6x-4y=-12

8x-3y = -2

2) Coeffcient Matrix : \begin{gathered} \left[\begin{array}{cc}6&-4\\8&-3\end{array}\right] \end{gathered}

[

6

8

−4

−3

]

Determinant ,D = (6*-3)-(-4*8)=-18+32=14

X-Matrix : \begin{gathered} \left[\begin{array}{cc}-12&-4\\-2&-3\end{array}\right]\end{gathered}

[

−12

−2

−4

−3

]

Determinant,Dx = (-12*-3)-(-2*-4) =36-8=28

Y-Matrix : \begin{gathered} \left[\begin{array}{cc}6&-12\\8&-2\end{array}\right]\end{gathered}

[

6

8

−12

−2

]

Determinant ,Dy = (6*-2)-(8*-12) = -12+96=84

3) Now,

By Cramer's Rule,

x= \frac{D_x}{D} = \frac{28}{14} = 2

D

D

x

=

14

28

=2

y= \frac{D_y}{D} = \frac{84}{14} = 6

D

D

y

=

14

84

=6

Hence , \boxed {x=2,y=6}

x=2,y=6

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