Question

Trigonometric Identities :
any 7

Answer 1

$\mathfrak{dear\;user }$

$\mathfrak{question-}$$\textsf{Trigonometric Identities :any 6}$

$\mathfrak{here\:is\:the\:solution\:for \:the question }$

$\boxed{\begin{minipage}{6cm} Important Trigonometric identities :- \\ \\ \: \: 1)\:\sin^2\theta+\cos^2\theta=1 \\ \\ 2)\:\sin^2\theta= 1-\cos^2\theta \\ \\ 3)\:\cos^2\theta=1-\sin^2\theta \\ \\ 4)\:1+\cot^2\theta=\text{cosec}^2 \, \theta \\ \\5)\: \text{cosec}^2 \, \theta-\cot^2\theta =1 \\ \\ 6)\:\text{cosec}^2 \, \theta= 1+\cot^2\theta \\\ \\ 7)\:\sec^2\theta=1+\tan^2\theta \\ \\ 8)\:\sec^2\theta-\tan^2\theta=1 \\ \\ 9)\:\tan^2\theta=\sec^2\theta-1 \end{minipage}}$

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$\mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}$

                                                                                    ʙʀᴀɪɴʟʏ  ʀᴏsʜᴀɴ

Answer 2

A Resource is something that can be used for a purpose. For example, tools and materials are resources. There are many kinds of resource:

Resource (Types and Developments), any natural or human wealth that can be used for satisfying human needs

Resource (economics), properties and opportunities which are used in the process of producing goods, including:

Natural resource, something that is valuable in its relatively natural form

Human resources (HR) or human capital, valuable human work power

Resource (project management), economic resources used in planning of tasks

Resource (computer science), files which contain data (like icons or images) to be used by a computer program, including

Resource (Web)

Uniform Resource Identifier

Uniform Resource Locator

Resource (Macintosh), data associated with a Mac OS file

Resource (Windows), data embedded in EXE and DLL files

Resource (Java), application data S E N D

+M O R E

M O N E Y

★SOLUTION

• from hint one above we see that M=1;

replace M By 1

S+M sold be at least 10 so as is my mother 9 if there is no carry over from the previous column aur 8 if there is a carry over.

S+Mm can only be 10 or 11 that means O can only be 0 or 1 but O cannot be 1 as M . Hence S=9.

In the hundredth kolam E+O=N,and O=0; but E cannot be the same as N; therefore there must be carried over from the previous column and N must be 1 greater than E:E+1=N.

from the N+R Kollam we can derive the equation: N+R+(+1) =E+10. we have to interest the expression (+1) Vikas we did not know yet another one is carried from over column D+E+10 p is inserted because we do know that one has to be carried over from the column N+R TO E+O.

subtract the first equation from the second: R+(+1)=9.

R cannot be equal to 9 since S=9, therefore R=8; p hence we know that one has to be carried over kolam D+E.

Column D+E mast total at least 12 since Y I cannot be 1 or 0 what values can we give D and E to reach his total? we have already used 9.8 else where the only digits left that are high enoug are 7,6and 7,5. but one of this has to be En,and N is 1 greater than E. hence E=5 and N=6 while D=7.

Then Y=2and the puzzle is solved The solution is:9767+1085=10652.