Math, asked by 9631485959, 8 months ago

(6x^5+4x^4-3x^3-1)÷(3x^2-x+1)​

Answers

Answered by Nilashri
2

Step-by-step explanation:

6x5+4x4-3x3-11-x+3x2

Final result :

6x5 + 4x4 - 3x3 + 3x2 - x - 11

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2". 3 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((((6•(x5))+(4•(x4)))-(3•(x3)))-11)-x)+3x2

Step 2 :

Equation at the end of step 2 :

(((((6•(x5))+(4•(x4)))-3x3)-11)-x)+3x2

Step 3 :

Equation at the end of step 3 :

(((((6•(x5))+22x4)-3x3)-11)-x)+3x2

Step 4 :

Equation at the end of step 4 :

(((((2•3x5) + 22x4) - 3x3) - 11) - x) + 3x2

Step 5 :

Trying to factor by pulling out :

5.1 Factoring: 6x5+4x4-3x3+3x2-x-11

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -3x3+3x2

Group 2: 6x5+4x4

Group 3: -x-11

Pull out from each group separately :

Group 1: (x-1) • (-3x2)

Group 2: (3x+2) • (2x4)

Group 3: (x+11) • (-1)

Looking for common sub-expressions :

Group 1: (x-1) • (-3x2)

Group 3: (x+11) • (-1)

Group 2: (3x+2) • (2x4)

Similar questions