Question

6x square +15xcube +21x power 4

Answer 1

HOLA USER ✌

HERE'S YOUR ANSWER FRIEND,

GIVEN : 6x² + 15x³ + 21x^4

SOLUTION ➡

ON DIVIDING THE WHOLE EQUATION BY 3x² we have,

==> 6x²/3x² + 15x³/3x² + 21x^4/3x²

==> 2 + 5x + 7x²

NOW, WE HAVE A QUADRATIC EQUATION.

==> 7x² + 5x + 6

==> NOW,

On comparing above equations with ax² + bx + c
we have,

a = 7, b = 5 and c = 6

NOW,

BY QUADRATIC FORMULA =

==> (-b ± √b² - 4ac)/2a

==> (-5 ± √5² - 4(7)(6))/2(7)

==> (-5 ± √25 - 168/14)

==> ( -5 ± √-143 /14)


THUS, x = (-5 + √143)/14 OR x = (-5 - √143)/14


ARE THE REQUIRED SOLUTIONS FOR x.

HOPE IT HELPS YOU.