Question

solve this ri8 now..its urgent...14 no.

Answer 1

In ∆ AGF ,
GF = 88.2-1.2 = 87 m
tan 30°= GF/ AF
1/√3= 87/AF
AF= 3× 87= 87√3

In∆ AHC,
tan 60°= CH/ AH
√3= 87/AH
AH= 87/√3

Distance moved
AF-AH
87√3-87/√3
87×3-87/√3
87(3-1)/√3
87(2)/√3
174/√3
or
58/√3.

✨Hope it helps you ✨