Question

6x square-underroot2x-2=0​

Answer 1

Answer:

$6 {x}^{2} - \sqrt{2} x - 2 = 0 \\ 6 {x}^{2} - 3 \sqrt{2}x - 2 \sqrt{2}x - 2 = 0 \\ 3 \sqrt{2}x ( \sqrt{2}x - 1) - 2( \sqrt{2}x - 1) = 0 \\ (3 \sqrt{2} x - 2)( \sqrt{2} x - 1) = 0 \\ so \\ x = \frac{2}{3 \sqrt{2} } \: or \: \frac{ \sqrt{2} }{3} \\ x = \frac{1}{ \sqrt{2} }$

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