Math, asked by mahaksolankimahak223, 1 year ago

6x(x-2)+6=0 find the value of x by quadratic formula..please its urgent..

Answers

Answered by niya25
1
6xsquare-12x+6=0
6 square-6x-6x+6
6x(x-1)- 6(x-1)
(6x-6) (x-1)=0
x=-1 or x=1

Anonymous: gud nt guys
Anonymous: yupp
Anonymous: ask it again
Anonymous: ohk
Anonymous: 6x ( x-2 ) + 6 = 0 => 6x² - 12x + 6 = 0 on comparing it with ax² + bx + c = 0 a = 6, b= -12, c = 6 we know, D = b² - 4ac = ( -12) ² - 4 (6) (6) =144-144 =0 hence, √D = 0 therefore, x = -b +- √D / 2a = -b / 2a ; -b / 2a = 12 / 12 ; 12/ 12 = 1 ; 1
Anonymous: hence, x is 1 or 1
Anonymous: samajh nhi ayegi tbhi bola tha ki question ek baar fir se puchho
Answered by sri00773
1

6x(x - 2) + 6 = 0 \\  \\ 6x ^{2}  - 12x + 6 = 0 \\  \\ (x - 1) {}^{2}  = 0 \\  \\ therefore \:  \:  \:  \: x  = 1
I hope it is the answer
Similar questions