Math, asked by swatisoni8d30, 7 months ago

6x (x+y-z) -x²y (xz-zy-xy) ​

Answers

Answered by kaviya08102001
2

Step-by-step explanation:

6x(x+y-z)-x^2y(xz-zy-xy)=0

-x^2y(xz-zy-xy)=-6x^2-6xy+6xz

÷(-)

x^2y(xz+zy+xy)=6x^2+6xy-6xz

÷xyz

x^3yz+x^2y^2z+x^3y^2=6x^2+6xy-6xz

xyz xyz xyz xyz xyz xyz

x^2+xy+x^2y = 6x + 6 - 6

z yz z y

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