6x (x+y-z) -x²y (xz-zy-xy)
Answers
Answered by
2
Step-by-step explanation:
6x(x+y-z)-x^2y(xz-zy-xy)=0
-x^2y(xz-zy-xy)=-6x^2-6xy+6xz
÷(-)
x^2y(xz+zy+xy)=6x^2+6xy-6xz
÷xyz
x^3yz+x^2y^2z+x^3y^2=6x^2+6xy-6xz
xyz xyz xyz xyz xyz xyz
x^2+xy+x^2y = 6x + 6 - 6
z yz z y
Similar questions