Question

Exercise 6.6
Solve the following:
1. PQR is triangle right angled at P. If PQ =10 cm and PR = 24 cm, find QR​

Answer 1

Step-by-step explanation:

In ∆PQR,ang.P=90°

By Pythagoras Thm,

QR^2=PQ^2+PR^2

=10^2+24^2

=100+576

=676

QR=√676

Hope this will help you

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Answer 2

Step-by-step explanation:

PQ=10cm

PR=24cm

Given:PQR is a right triangle

by pytagorus theorem

RP*RP+PQ*PQ=QR*OR

576+100=QR*QR

676=QR*QR

26=QR