Question

6x2–3–7x find the zeroes of the quadratic polynomial ​

Answer 1

Answer:

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Answer 2

Solution :

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$\underline{\underline{{\purple{\sf Given}}}}$

Step-by-step explanation:

$\bigstar$ $\bf{6x^2-3-7x}$

$\ \implies$ $\sf{ ie,6x^2-7x-3=0}$

$\ \implies$ $\bf{By \:Factorization\: of\: numbers:}$

$\longrightarrow$ $\sf{6x²-7x-3=0}$

$\longrightarrow$ $\sf{6x²-9x+2x-3=0}$

$\longrightarrow$ $\sf{3x(2x-3)+1(2x-3)=0}$

$\longrightarrow$ $\sf{(2x-3)(3x+1)=0}$

$\longrightarrow$$\sf{x=\dfrac{3}{2} andx=\dfrac{-1}{3}}$

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