Question

6x² + 5x-1=0
solve for x?????​

Answer 1

Answer:

6x^2 + 5x - 1 =0

6x^2 - x + 6x - 1 =0

x (6x - 1) +1(6x - 1) =0

(x + 1) (6x - 1) =0

x =-1 , x = 1/6

Answer 2

The value of x = -1 and x = 1/6

Solution

Given expression is:

$6x^2 + 5x - 1 = 0$

We have to solve for "x"

From given,

$6x^2 + 5x - 1 = 0\\\\Split\ the\ middle\ term\\\\6x^2-x + 6x -1 = 0\\\\\mathrm{Break\:the\:expression\:into\:groups}\\\\\left(6x^2-x\right)+\left(6x-1\right) = 0\\\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}6x^2-x\\\\x\left(6x-1\right)+\left(6x-1\right) = 0\\\\\mathrm{Factor\:out\:common\:term\:}6x-1\\\\\left(6x-1\right)\left(x+1\right) = 0$

Thus,

$6x - 1 = 0\\\\6x = 1\\\\x = \frac{1}{6}\\\\And\\\\x + 1 = 0\\\\x = -1$

Thus, x = -1 and x = 1/6

Learn more about this topic

Solve for x:(5x+1)(x+3)-8=5(x+1)(x+2)

https://brainly.in/question/1088430

√217-x = x-7 solve for x

https://brainly.in/question/3369043