Question

6x2-7x+2 complete the square method

Answer 1

Answer:

The discriminant = b² – 4ac

= 49 – 4 × 6 × 2

= 1 > 0

So, the given equation has two distinct real roots.

Now, 6x² – 7x + 2 = 0

i.e., 36x² – 42x + 12 = 0

i.e., 6x - (7/2)²+ 12 - 49/4 = 0

i.e., 6x - (7/2)²- (1/2)²= 0

or (6x - 7/2)² = (1/2)² The roots are given by

6x - 7/2 = ±1/2 i.e., 6x = 4, 3 i.e., x = 2/3, 1/2.