Question

6x²+x-12=0(solve the quadratic equation by factorisation)

Answer 1

Answer:

$6 {x}^{2} + x - 12 = 0 \\ = 6 {x}^{2} + 9x - 8x - 12 = 0 \\ = 3x(2x + 3) - 4(2x + 3) = 0 \\ = (2x + 3)(3x - 4) = 0 \\ x = \frac{ - 3}{2} \: \: and \: \: \frac{4}{3}$

Here is your solution. Thanks ❤️