Question

6x²-x-2=0
find the route of QE​

Answer 1

Answer:

ok it will help u

these are correct values

Answer 2

Answer:

we have,

6x²-x-2=0

6x²+3x-4x-2=0

3x(2x+1)-2(2x+1)=0

(2x+1)(3x-2)=0

so, 2x+1=0

2x=0-1

x= -1/2

or

3x-2=0

3x=2

so, x= 2/3

Hence , -1/2 and 2/3 are the zeros of the given quadratic polynomial.