Question

6x2 + x - 2 by formula method ( quadratic equation )

Answer 1

Step-by-step explanation:

given equation is

$6 {x}^{2} + x - 2 = 0$

compare with

$a {x}^{2} + bx + c = 0$

$a = 6 \: \: \: b = 1 \: \: \: c = - 2$

$x = \frac{ - b <u>(</u><u>+</u><u> </u>or - )\sqrt{ {b}^{2} - 4ac} }{2a}$

$x = \frac{( - 1) <u>+</u> or - \sqrt{ {(1)}^{2} - 4 \times (6) \times ( - 2) } }{2 \times (6)}$

$x = \frac{( - 1) <u>+</u>or -\sqrt{1 + 48} }{12}$

$x = \frac{( - 1) <u>+</u> or - \sqrt{49} }{12}$

$x = \frac{( - 1) <u>+</u><u> </u><u>o</u><u>r</u><u> </u>-7}{12}$

therefor the roots are

$x = \frac{ - 1 + 7}{12} = \frac{6}{12} = \frac{1}{2}$

OR

$x = \frac{ - 1 - 7}{12} = \frac{ - 8}{12} = \frac{ - 2}{3}$