6x2 +x=2 solve this equation by completing square method
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6x^2 + x = 2
On dividing whole equation by 6, we get
=> x^2 + x/6 = 2/6
Add (1/12)^2 in both sides
=> x^2 + x/6 + ( 1/12)^2 = 2/6 + (1/12)^2
=> ( x + 1/12)^2 = 2/6 + 1/144
=> ( x + 1/12)^2 = ( 48 + 1) /144
=> ( x + 1/12)^2 = 49 / 144
=> x + 1/12 = plus minus 7 / 12
=> x = -1/12 + - 7/12
Alpha = - 1/12 + 7 /12
= ( - 1+ 7) /12
= 6/12
= 1/2
Beta = - 1/12 - 7/12
= (-1 - 7) / 12
= - 8 /12
= - 3 /4
On dividing whole equation by 6, we get
=> x^2 + x/6 = 2/6
Add (1/12)^2 in both sides
=> x^2 + x/6 + ( 1/12)^2 = 2/6 + (1/12)^2
=> ( x + 1/12)^2 = 2/6 + 1/144
=> ( x + 1/12)^2 = ( 48 + 1) /144
=> ( x + 1/12)^2 = 49 / 144
=> x + 1/12 = plus minus 7 / 12
=> x = -1/12 + - 7/12
Alpha = - 1/12 + 7 /12
= ( - 1+ 7) /12
= 6/12
= 1/2
Beta = - 1/12 - 7/12
= (-1 - 7) / 12
= - 8 /12
= - 3 /4
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0
Answer:
6x2+x=2 completing squre method
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