Question

(6x2 –x+8)(x2 -3) factorise

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Answer 1

The factorised answer is as follows

Answer 2

${\huge {\underline {\mathfrak {\green {Question}}}}}$

(6x2 –x+8)(x2 -3) factorise

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${\huge {\underline {\mathfrak {\green {Answer}}}}}$

= $(6 {x}^{2}- x + 8)({x}^{2} - 3)$

${\tt {\blue {\bigstar{Multiply\:each\:terms}}}}$

= $6{x}^{2}({x}^{2} - 3)-x ({x}^{2}-3)+8 ({x}^{2}-3)$

${\tt {\blue {\bigstar{Distribute\: 6 {x}^{2}\:through \:the\:parentheses}}}}$

= $6{x}^{4}-{18x}^{2}-{x}^{3}+3x+8{x}^{2}-24$

${\tt {\blue {\bigstar{Collect\:like\:term}}}}$

= $6{x}^{4}-{10x}^{2}-{x}^{2}+3x-24$

${\tt {\blue {\bigstar{Use\:commutative\:property\:to\:reorder}}}}$

= $6{x}^{4}-{x}^{3}-{10x}^{2}+3x-24$

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