Question

6xsquare-3-7x find the zero of following quadratic polynomials

Answer 1

Answer:

(3x + 1)(2x - 3)

Step-by-step explanation:

$6x^2 - 7x -3\\6x^2 - 9x + 2x -3\\3x(2x - 3) + 1(2x - 3)$

(3x + 1)(2x - 3)

zeroes are -1/3,3/2