Question

6xsquare-x-2 Find the zeros of the polynomial

Answer 1

Answer:

$6x {}^{2} - x - 2 \\ 6x {}^{2} - 4x + 3x - 2 \\ 2x(3x - 2) + 1(3x - 2) \\ (2x + 1)(3x - 2) \\ therefore \\ x = - \frac{1}{2} \: and \: \frac{2}{3}$

Step-by-step explanation:

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Answer 2

Answer:

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