Math, asked by patilsuchita590, 8 months ago

6y+1/3+1=y-3/6 this one is of solving equations from both sides​

Answers

Answered by rkuntal7686
2

Answer:

6y +  \frac{1}{3} + 1 = y -  \frac{3}{6}

6y - y =  -  \frac{3}{6} -  \frac{1}{3}  - 1

5y =  \frac{ - 3 - 2 - 6}{6}  =  \frac{ - 11}{6}

y =  \frac{ - 11}{6}  \times  \frac{1}{5}

y =  \frac{ - 11}{30}

Answered by Anonymous
0

Answer:

-\frac{11}{30}

Step-by-step explanation:

6y + \frac{1}{3\\} + 1 = y  -\frac{3}{6}

6y - y + 1 =  -\frac{3}{6}  -\frac{1}{3\\}

LCM = 6

5y + 1 =  -\frac{3}{6} -\frac{2}{6}

5y + 1 = -\frac{5}{6}

5y = -\frac{5}{6} -1

5y =  -\frac{5}{6} -\frac{6}{6}

5y = -\frac{11}{6}

y = -\frac{11}{6} ÷ \frac{5}{1}

y = -\frac{11}{30}

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