Question

6y +5/7 =3/5
what is the solution for the above equation ​

Answer 1

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Answer 2

AnswEr:-

↦ Your Answer Is $\tt -\dfrac{2}{105}$.

ExplanaTion:-

Given equation:-

$\\ \tt\longrightarrow6y + \dfrac{5}{7} = \dfrac{3}{6} .$

To Find:-

• The solution (i.e the value of y) in the given equation.

Concepts Used:-

↦ While Transporting any number from LHS to RHS or RHS To LHS:-

• (+) becomes (-)
• (-) becomes (+)
• (÷) becomes (×)
• (×) becomes (÷)

↦So lets solve the given equation by using above comcepts:-

$\\ \\ \tt\mapsto6y + \dfrac{5}{7} = \dfrac{3}{5} . \\ \\ \tt\mapsto6y = \dfrac{3}{5} - \dfrac{5}{7}. \\ \\ \rm(transporting \: \: \frac{5}{7} \: \: to \: \: rhs). \\ \\ \tt\mapsto6y = \dfrac{3(7) - 5(5)}{(5)(7)} .\\ \\ \rm(taking \: \: lcm). \\ \\ \tt\mapsto6y = \dfrac{21 - 25}{35} . \\ \\ \tt\mapsto6y = - \dfrac{ 4}{35} . \\ \\ \tt\mapsto y = - \dfrac{4}{35 \times 6} \\ \\ \rm(transporting \: \:6 \: \: to \: rhs). \\ \\ \tt\mapsto y = - \cancel\dfrac{4}{210}. \\ \\ \tt\mapsto y = -\dfrac{2}{105}.$

$\therefore$ The required value of y is $\tt -\dfrac{2}{105}$.