Math, asked by parveengill1663, 9 months ago

6y+(6y+12)²=12 then find the value of y

Answers

Answered by Shrivivek
0

Answer:

y= -25+√97. or. y=-25-√97

12. 12

Step-by-step explanation:

6y+(6y+12)²=12

6y+(6y)²+2×6y×12+12²=12

6y+36y²+144y+144=12

150y+36y²=12-144

36y²+150y= -132

dividing through out by 6 we get,

6y²+25y= -22

6y²+25y+22=0

comparing with the general form

ax²+bx+c =0 we get,

a=6 b=25 c=22

b²-4ac

=(25)²-4×6×22

=625-528

=97

Using formula

y = -b ±√b²-4ac

2a

y = -25±√97

12

y= -25+√97. or. y=-25-√97

12. 12

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