Question

6y4-19y3-23y2+10y+8 factorise this​

Answer 1

Answer:

The factors are: (y+1)(y-4)(3y-2)(2y+1)

Step-by-step explanation:

Given that,

$6y^{4}-19y^{3}-23y^{2}+10y+8\\=6y^{3} (y+1)-25y^{2}(y+1)+2y(y+1)+8(y+1)\\=(y+1)(6y^{3}-25y^{2}+2y+8)\\=(y+1)[6y^{2}(y-4)-y(y-4)-2(y-4)]\\=(y+1)(y-4)(6y^{2}-y-2)\\=(y+1)(y-4)(6y^{2}-4y+3y-2)\\=(y+1)(y-4)[2y(3y-2)+1(3y-2)]\\=(y+1)(y-4)(3y-2)(2y+1)$

∴$6y^{4}-19y^{3}-23y^{2}+10y+8=(y+1)(y-4)(3y-2)(2y+1)$

_______________________

           //Hope it will Helped You//

       //Please Mark it as Brainliest//