Question

[7(2 - y) - 5(y +12)] - 3y + 6 = 5
check the solution
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Answer 1

Step-by-step explanation:

$(14 - 7y - 5y - 60) - 3y + 6 - 5 = 0 \\ - 46 - 12y - 3y + 1 \\ - 45 - 15y = 0 \\ - 15y = 45 \\ y = \frac{45}{ - 15} = - 3 \\ y = - 3$

Answer 2

Answer:

y = - 3 is not the solution of the given equation.

Step-by-step-explanation:

We have given that,

[ 7 ( 2 - y ) - 5 ( y + 12 ) ] - 3y + 6 = 5

We have to find the solution of the equation.

Now,

[ 7 ( 2 - y ) - 5 ( y + 12 ) ] - 3y + 6 = 5

⇒ [ 14 - 7y - 5y - 60 ] - 3y + 6 = 5

⇒ 14 - 7y - 5y - 60 - 3y + 6 = 5

⇒ - 7y - 5y - 3y + 14 - 60 + 6 = 5

⇒ - 7y - 8y + 14 + 6 - 60 = 5

⇒ - 15y + 20 - 60 = 5

⇒ - 15y - 40 = 5

⇒ - 15y = 5 + 40

⇒ - 15y = 45

⇒ - y = 45 ÷ 15

⇒ - y = 3

⇒ y = - 3

∴ The value of y is - 3.

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Verification:

The given equation is [ 7 ( 2 - y ) - 5 ( y + 12 ) ] - 3y + 6 = 5.

We have y = - 3.

By substituting y = - 3 in the LHS of the given equation, we get,

[ 7 ( 2 - y ) - 5 ( y + 12 ) ] - 3y + 6 = 5

LHS = [ 7 ( 2 - y ) - 5 ( y + 12 ) ] - 3y + 6

⇒ LHS = { 7 [ 2 - ( - 3 ) - 5 [ ( - 3 ) + 12 ] } - 3 * ( - 3 ) + 6

⇒ LHS = [ 7 ( 2 + 3 ) - 5 ( - 3 + 12 ) ] 9 + 6

⇒ LHS = [ ( 7 * 5 ) - ( 5 * 9 ) ] 15

⇒ LHS = ( 35 - 45 ) 15

⇒ LHS = - 10 * 15

⇒ LHS = - 150

RHS = 5

∴ LHS ≠ RHS

∴ y = - 3 is not the solution of the given equation.