Question

7,290 in 3 years, then find a
cost reduces to
The cost of a washing machine is 10,000. If it cost
depreciation.​

Answer 1

Answer:

Step-by-step explanation:

total value decreased is 10000-7290=2710

so it 2710 is decreased in 3 years therefore price decreased in 1 year will be 2710÷3=903.33 rs

therefore percentage decrease in rate of washingmachine will be (903.33×100)÷10000

which is = 90333÷10000=9.03%

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Answer 2

Answer:

The rate of depreciation is 10%

Step-by-step explanation:

Let the rate of depreciation is r

cost of washing machine after 1st year

$=10000-10000\times r/100$

$=10000(1-\frac{r}{100})$ Rs.

Cost of washing machine after 2nd year

$=10000(1-\frac{r}{100})-10000(1-\frac{r}{100})\times \frac{r}{100}$

$=10000(1-\frac{r}{100})(1-\frac{r}{100})$

$=10000(1-\frac{r}{100})^2$

In a similar way we can find that the cost of machine after 3 years will be

$=10000(1-\frac{r}{100})^3$

According to the question

$10000(1-\frac{r}{100})^3=7290$

$\implies (1-\frac{r}{100})^3=\frac{729}{1000}$

$\implies (1-\frac{r}{100})^3=(\frac{9}{10})^3$

$\implies 1-\frac{r}{100}=\frac{9}{10}$     (Taking cube root on both the sides)

$\implies \frac{r}{100}=1-\frac{9}{10}$

$\implies \frac{r}{100}=\frac{1}{10}$

$\implies r=\frac{100}{10}=10$

Therefore, the rate of depreciation is 10%

Hope this helps.