Question

7^2n+3-(49)^n+2/((343)^n+1)^2/3

Answer 1

here is your answer -42

Answer 2

Concept: The exponent of a number indicates how many times a number has been multiplied by itself. For instance, $3^4$ indicates that we have multiplied 3 four times. Its full form is 3 × 3 × 3 × 3. Exponent is another name for a number's power. A whole number, fraction, negative number, or decimal are all acceptable.

Exponent-related problems are solved using the rules of exponents or the properties of exponents. These characteristics are regarded as major exponents rules that must be adhered to when solving exponents. The following list includes exponent qualities.

• $a^m * a^n = a^m^+^n$
• $a^m / a^n = a^m^-^n$
• $a^0 = 1$
• $a^-^m = \frac{1}{a^m}$
• $(a^m)^n = a^m^n$

Given: $\frac{7^2^n^+^3 - 49^n^+^2}{[343^n^+^1]^\frac{2}{3} }$

To find: the value of $\frac{7^2^n^+^3 - 49^n^+^2}{[343^n^+^1]^\frac{2}{3} }$

Solution:

As it is given that

$\frac{7^2^n^+^3 - 49^n^+^2}{[343^n^+^1]^\frac{2}{3} } \\\\\frac{7^2^n^+^3 - [(7)^2]^n^+^2}{[(7^3)^n^+^1]^\frac{2}{3} } \\\\\frac{7^2^n^+^3 - 7^2^n^+^4}{[7^3^n^+^3]^\frac{2}{3} } \\\\\frac{7^2^n*7^3 - 7^2^n*7^4}{7^2^n^+^2} \\\\\frac{7^2^n[7^3-7^4]}{7^2^n*7^2} \\\\\frac{7^3[1-7]}{7^2} \\\\7[-6]\\\\-42$

Hence, the answer is -42.

#SPJ2