7/2x+1+13/y+2=27 ; 13/2x+1+7/y+2=33solve this eqution
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7/2x+1+13/y+2=27
=let 1/x=a and 1/y=b
=7a/2+1+13b+2=27
=7a+1*2+13b*2+2*2/2=27
=7a+2+26b+4=27*2
=7a+26b+6=54{equation 1}
13/2x+1+7/y+2=33
=let 1/x=a and 1/y=b
=13a/2+1+7b+2=33
=13a+1*2+7b*2+2*2/2=33
=13a+2+14b+4=33*2
=13a+14b+6=66{equation 2}
then using elimination method,find value of 1/a\1/b and then substitute it in any one equation.you will get the answer.
=let 1/x=a and 1/y=b
=7a/2+1+13b+2=27
=7a+1*2+13b*2+2*2/2=27
=7a+2+26b+4=27*2
=7a+26b+6=54{equation 1}
13/2x+1+7/y+2=33
=let 1/x=a and 1/y=b
=13a/2+1+7b+2=33
=13a+1*2+7b*2+2*2/2=33
=13a+2+14b+4=33*2
=13a+14b+6=66{equation 2}
then using elimination method,find value of 1/a\1/b and then substitute it in any one equation.you will get the answer.
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